Combining Errors for Trigonometric Functions: Understanding the Formula

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Homework Help Overview

The discussion revolves around the propagation of errors in a trigonometric function, specifically the relationship r = (D/2)sin(4θ). Participants are exploring how to apply error propagation formulas to this context, particularly in relation to trigonometric identities and their derivatives.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to apply a standard combination of errors formula but are encountering confusion regarding the transformation of sine to tangent and the reasoning behind the coefficients in the error formula. There is also discussion about treating sin(4θ) as a separate component and the potential use of a Maclaurin series for simplification.

Discussion Status

Some participants have provided links to resources on error propagation, while others express difficulty in understanding the terminology and concepts. There is an ongoing exploration of the derivatives involved and their significance in the context of the problem. Multiple interpretations of the error propagation approach are being considered.

Contextual Notes

Participants are grappling with the complexity of the symbols and the nonlinear nature of the function. There is mention of independent errors and the need for clarity on the derivatives of trigonometric functions as they relate to the overall error calculation.

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This is just my own practise question.

I have a relationship of

r = \frac{D}{2}sin4\theta

The apparent error formula is now:

\left(\frac{\Lambda r}{r}\right)^{2} = \left(\frac{\Lambda D}{D}\right)^{2} + 16 \left(\frac{\Lambda \theta}{tan 4 \theta}\right)^{2}


Using a standard combination of errors formula, I only get

\left(\frac{\Lambda r}{r}\right)^{2} = \left(\frac{\Lambda D}{D}\right)^{2} + 16 \left(\frac{\Lambda \theta}{4 \theta}\right)^{2}

Since I know there would be an error in the measurement of the angle. The 16 I'm also unsure of anyway, I just guessed you had to square the 4 and put it on the outside. How to you do errors for trigonometric identities is what I want to know. How do you go from sin to tan and what is the reasoning behind what they did and came out with?

Here is the error formula I think I am supposed to use

\left(\frac{\Lambda F }{F}\right)^{2} = k^{2} \left(\frac{\Lambda A}{A}\right)^{2} + l^{2} \left(\frac{\Lambda B}{B}\right)^{2}




Thank you for any help
 
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K I've decided I should treat sin 4 /theta as a separate piece. But it still doesn't help. What is Sine, how can I change it into a power?

How do I solve this crap lol
 
The symbols are confusing me sorry. Should I use a maclaurin series for sin (at least that way I would have a linear function).

Can you please explain your link?
 
Your function r is a nonlinear function of two variables, and the link shows how to determine the variance \sigma_r^2 (what you are calling (\Lambda r)^2). You don't need to expand the sine term, but you do need to know its derivative.
 
Lets do it step by step, the link has too much jargon and I simply can't understand it.

K the derivative of sine 4 is 4 cos 4

What importance does this have on our relationship?
 
The key equation is

\sigma_f^2=\left(\frac{\partial f}{\partial a}\right)\sigma_a^2+\left(\frac{\partial f}{\partial b}\right)\sigma_b^2

for a function f(a,b), where the errors are independent (i.e., the covariance \mathrm{COV}=0).

Your function is r(D,\theta). Try working through the entire equation.
 
Equation doesn't work, it's like I have to fluke my way to get the answer.
 

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