- #1

ELLE_AW

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## Homework Statement

__An object of mass m=2.3±0.1kg moves at a speed of v=1.25±0.03m/s. Calculate the kinetic energy (K=1/2mv2) of the object and estimate the uncertainty δK?__

## Homework Equations

- Addition error propagation--> z = x + y and the Limit error--> δz = δx + δy

- Exponent error propagation --> z = xn and the Limit Error --> δz = nx

^{n-1}(δx)

- K = 1/2mv

^{2}

## The Attempt at a Solution

This is what I attempted, but I really don't think it's right. I basically just included the exponent error propagation, but how does the multiplication of mv

^{2}get incorporated?

- K = ½ mv2 = ½ (2.3kg)(1.25m/s)

^{2}= 1.7969 kg m

^{2}s

^{-2}= 1.8 J

- Uncertainty of K = (m)2v

^{1}(δv) = (2.3)(2)(1.25)(0.03) = 0.1725 = 0.17

**How do I combine these two rules when calculating the uncertainty of the kinetic energy?**