Combining Proportionality Statements

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The discussion centers on the mathematical implications of combining proportionality statements, specifically "a ∝ b" and "a ∝ c". Participants clarify that these statements imply a relationship where a can be expressed as a product of constants and variables, leading to the conclusion that a = kbc, where k is a constant of proportionality. The conversation explores the nuances of defining constants and variables in the context of proportionality, ultimately concluding that while a = bc suggests a direct relationship, the constants involved must be carefully defined to avoid contradictions in variable behavior.

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prosteve037
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If you have two statements, "a ∝ b" and "a ∝ c", you would get: "a = xb" and "a = yc" (where x and y are the constants of proportionality)

But what do you do so that it turns out to be "a = b × c"?

I've been searching for a DETAILED MATHEMATICAL explanation but have failed in finding one that responds thoroughly to my inquiry. I mean, I understand how it would result in "a = bc", but I'm having trouble understanding how to get there in concise mathematical steps and easy-to-understand mathematical reasoning.
 
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If anything, I would intuitively think that "a ∝ b" and "a ∝ c" imply "a ∝ bc", and thus a = kbc, where k is a constant of proportionality.

EDIT:
Actually, I'm wrong.

First, some definitions:
-to say of two variables a and b that "a ∝ b" means there exists a nonzero real constant k such that a = kb

"a ∝ b" and "a ∝ c" imply a = bk and a = jc for some nonzero k, j in R, respectively.
Then bc = (a/k)(a/j) = a2/(kj) and so a2 = (kj)bc, where (kj) is the product of two arbitrary constants in R and is thus itself an arbitrary constant in R. Therefore a2 ∝ bc.

EDIT 2: And in fact, a = bc would imply that a2 = (kj)bc = (kj)a, implying a = kj = constant. But a is a variable!
 
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This may be a quibble, but a=b x c means a ~ b where c is constant and a ~ c where b is constant.
 
Hmm. Is there no way to prove that "k = c" and "j = b" though?
 
mathman said:
This may be a quibble, but a=b x c means a ~ b where c is constant and a ~ c where b is constant.

I've been thinking about this and somehow it managed to clear things up a lot haha. Thank you.

But now there's something bothering me about this description; if you hold one variable constant, how can you say that that same variable is the constant of proportionality?

Looking at this now, this seems more of a general science question than it is a math question...

EDIT: What I mean is that given this description of what proportionality statements signify about dependent and independent/constant variables, do we just ASSIGN the constant variables to constants of proportionalities?
 
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mathman said:
This may be a quibble, but a=b x c means a ~ b where c is constant and a ~ c where b is constant.

Yes, sorry, I should have included that as well.

Here's something I found though that explains the procedure a bit better (page 243, #389). What I don't understand though is why the two cases are taken consecutively (ie. the author goes from \frac{A}{a'} to \frac{a'}{a}). Is this the only way to reason this without paying attention to what the proportionality constants are dependent on?
 
Saying "a ∝ b" means a= kb (k constant) all other factors held constant. saying "a ∝ c" means a= hc (h constant) all other factors held contstant. That tells you that the "k" in a= kb includes c as a factor (which is being held constant) and that the "h" in a= hc includes b as a factor (which is being held contstant). The two together tell you that a= jbc where j is a constant (as long as all other factors are held constant.
 

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