Comet Speed at 6x10^12 m from Sun

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The discussion focuses on calculating the speed of a comet at a distance of 6x1012 m from the Sun, which is approximately the distance of Pluto. At its closest approach, the comet reaches a speed of 9.6x104 m/s when it is 4.7x1010 m from the Sun. The calculation involves applying the conservation of energy principle, where the potential and kinetic energies at the closest point are compared to the potential energy at the farther distance. The mass of the comet can be canceled out in the equations, simplifying the calculation.

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A comet is in an elliptical orbit around the Sun. Its closest approach to the Sun is a distance of 4.7x10^10 m (inside the orbit of Mercury), at which point its speed is 9.6x10^4 m/s. Its farthest distance from the Sun is far beyond the orbit of Pluto. What is its speed when it is 6x10^12 m from the Sun? (This is the approximate distance of Pluto from the Sun.)



I have no idea how to do this can someone please help?
 
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conservation of energy. You know the potential energy and the kinetic energy at the closest point to the sun, and the potential energy at 6*10^12 m. All energies will contain the mass of the comet, but you can cancel that. You'll have to look up the mass of the sun.
 

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