What Does It Mean for a Function to Have Compact Support?

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A function f: R -> R is said to have compact support if it is zero outside of a finite closed interval, meaning its support is contained within a compact set. This means that f vanishes at positive and negative infinity, but the two concepts are not interchangeable. The Gaussian function, while never zero, does vanish at infinity and therefore does not have compact support. The misunderstanding arises from conflating the definitions of support and behavior at infinity. In summary, compact support specifically refers to the function being zero outside a bounded interval.
mnb96
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Hello,
given a function f:R->R, can anyone explain what is meant when we say that "f has compact support"?

Some sources seem to suggest that it means that f is non-zero only on a closed subset of R.
Other sources say that f vanishes at infinity. This definition seem to contradict the previous: for example the Gaussian is never 0 but does vanish at infinity.

So, where is the misunderstanding?
 
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Compact support means the function is zero everywhere outside some finite interval. Gaussian does not have compact support.
 
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It naturally means that the support of the function is a compact set, or equivalently as mathman points out; contained in a finite closed interval. This implies that f must vanish at positive and negative infinity, but is not equivalent as your example shows.
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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