Compare LHS and RHS: Solve Problem Equation

[zak100]

Homework Statement

LHS
(3y+2)/5
RHS
y

Which is greater?

Homework Equations

Equation is provided in the question

The Attempt at a Solution

let y=1:
LHS= 1
RHS=1
So LHS & RHS are equal.

2ND try;
LET Y=0
LHS= 0.4
RHS= 0
So LHS is greater.
So Answer can't be determined using the information provided.

However my answer not correct. Some body please guide me.

Zulfi.

 

[FactChecker]

Do you know how to find the values of y where they are equal? If so, you can just test once in each of the other sections and see how they compare.

 

[Buffu]

Homework Statement

LHS
(3y+2)/5
RHS
y

Which is greater?

Homework Equations

Equation is provided in the question

The Attempt at a Solution

let y=1:
LHS= 1
RHS=1
So LHS & RHS are equal.

2ND try;
LET Y=0
LHS= 0.4
RHS= 0
So LHS is greater.
So Answer can't be determined using the information provided.

However my answer not correct. Some body please guide me.

Zulfi.

$f(y) := (3y+2)/5 - y = (3y + 2 - 5y)/5 = (2 - 2y)/5$

$f(y) > 0$ for $y < 1$ and negative elsewhere. So I think you are correct.

Maybe the domain is mentioned. did you wrote exact question ?

 

[zak100]

Hi,
Thanks. You are right. I skipped the assumption:
y>4. Now if y=5 then:
LHS= 17/3= 3.666
RHS=5 so RHS is greater.

Let y=20
LHS= 62/5= 12.4
RHS= 20

so again RHS is greater.

So RHS is greater.

Thanks for your comment.

Zulfi.

 

[Mark44]

LHS
(3y+2)/5
RHS
y

Assuming, as you later wrote, that y > 4, solve the inequality (3y + 2)/5 > y. This is equivalent to y < 1.
This means that if y < 1, the left side will be larger than the right side.

Put another way, if y < 1, the right side will be smaller than the left side. If y > 1, the right side will be larger. Your two examples, with y = 5 and y = 20 both support this conclusion.