Comparing mass ratios and 'proving the law of multiple proportions holds true'

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SUMMARY

The discussion centers on comparing the mass ratios of nitrogen oxides, specifically N2O3 and N2O5, to demonstrate the law of multiple proportions. The calculations provided show that for N2O3, the mass of nitrogen is 28g and oxygen is 48g, while for N2O5, nitrogen remains at 28g and oxygen increases to 80g. The resulting ratios indicate that the ratio of the masses of oxygen in N2O3 and N2O5 is 5:3, confirming that the law of multiple proportions holds true as the mass ratios of oxygen can be expressed as simple whole numbers.

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Owelode
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Compare the mass ratios of N2O3 and N2O5 and prove the law of multiple proportions holds true.


I'm having trouble understanding what the question is asking for. So far, I've done this:



N2O3:

N: 14g * 2 = 28g

O: 16g * 3 = 48g


N2O5:

N: 14g * 2 = 28g

O: 16g * 5 = 80g


28g N * 80g O = 5
48g O * 28g N = 3

I'm not sure what ratio I found or what to do with those numbers, so any help would be appreciated.
 
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State law of multiple proportions, that will be a good starting point.
 

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