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Comparing the real (integer part) of a number.

  1. Feb 29, 2012 #1
    1. The problem statement, all variables and given/known data

    Compare between E(x+y) and E(x)+E(y) for every real number x and y.

    E() refers to the real integer part of the number.


    3. The attempt at a solution

    Well I know that we have to split it up into 3 cases. One for which both are positive, both negative, and one of them is negative. For example I know when we have x and y greater than 0 we get E(x+y)≥E(x)+E(y) because let's take x=1.5 and y=1.6 then E(1.5+1.6)= 3 and
    E(1.5)+E(1.6)= 2. Can anyone help me come up with a proof for this?
     
  2. jcsd
  3. Feb 29, 2012 #2
    Anyone have any ideas.
     
  4. Feb 29, 2012 #3

    Mark44

    Staff: Mentor

  5. Mar 1, 2012 #4
    Alright Thank You I came up with a proof from what i read on wiki.
     
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