Completeness Relation: Significance & Multiplying State Vector

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The completeness relation in quantum physics, expressed as the sum of outer products of basis states equaling one, signifies that any state vector can be represented as a linear combination of these orthonormal basis states. This relationship allows for the expansion of a state vector |ψ⟩ in terms of its coefficients, which are derived from the inner products ⟨n|ψ⟩. In practical terms, this means that the state vector can be expressed in different representations, such as the position representation, where it is written as a sum of basis functions multiplied by their respective coefficients. The completeness relation is crucial for ensuring that all possible states are accounted for in quantum mechanics. Understanding this concept is fundamental for analyzing quantum systems and their behaviors.
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hi, in quantum physics completeness relation is often use it equals to one - what is its significance in multiplying with state vector . thanks
wasi
 
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Do you mean this:

$$\sum {| n \rangle \langle n |} = 1\\
\sum {| n \rangle \langle n | \psi \rangle} = | \psi \rangle$$

This represents the expansion of ##|\psi\rangle## into a linear combination of orthonormal basis states ##|n\rangle##. The ##\langle n | \psi \rangle## are the coefficients of the expansion. In the position representation we usually write this as something like

$$\psi(x) = \sum {c_n \psi_n(x)}$$
 
Time reversal invariant Hamiltonians must satisfy ##[H,\Theta]=0## where ##\Theta## is time reversal operator. However, in some texts (for example see Many-body Quantum Theory in Condensed Matter Physics an introduction, HENRIK BRUUS and KARSTEN FLENSBERG, Corrected version: 14 January 2016, section 7.1.4) the time reversal invariant condition is introduced as ##H=H^*##. How these two conditions are identical?

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