Complex analysis: Find a function that maps z1 and z2 onto w1 and w2

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SUMMARY

The discussion centers on finding a linear transformation function that maps the complex numbers z1 = 2 and z2 = -3i to w1 = 1+i and w2 = 3. The textbook solution provided is w = f(z) = (3+2i)/13 * z + (7+9i)/13. However, participants identified inconsistencies in the mapping, particularly with the second output, leading to the conclusion that w2 should actually be 1, not 3. The correct approach involves using linear transformations and solving simultaneous equations for the complex constants a and b.

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Juwane
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Homework Statement



What is the function (linear transformation) that maps z_{1} = 2 and z_{2} = -3i onto w_{1} = 1+i and w_{2} = 3?

I think it's asking for the function that if you put 2 in it, it should give 1+i, and if you put -3i in the same function, it should give 3.

The answer given at the back of the book is w=f(z)=\frac{3+2i}{13}z + \frac{7+9i}{13}

Homework Equations



Maybe these would help:

x = \frac{z + \overline{z} }{2} and y = \frac{z - \overline{z} }{2i}

The Attempt at a Solution



I have no idea how to even start. The horrible book I am using doesn't give a clue. One possible way is to see what do we have to z_{1} = 2 to get 1+i. The answer is: -1+i , but we can't add this to z_{2} = -3i, since that would give us 1-2i whereas we must get 3. Is there any other way to find out?
 
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Juwane said:

Homework Statement



What is the function (linear transformation) that maps z_{1} = 2 and z_{2} = -3i onto w_{1} = 1+i and w_{2} = 3?

I think it's asking for the function that if you put 2 in it, it should give 1+i, and if you put -3i in the same function, it should give 3.

The answer given at the back of the book is w=f(z)=\frac{3+2i}{13}z + \frac{7+9i}{13}

Homework Equations



Maybe these would help:

x = \frac{z + \overline{z} }{2} and y = \frac{z - \overline{z} }{2i}

The Attempt at a Solution



I have no idea how to even start. The horrible book I am using doesn't give a clue. One possible way is to see what do we have to z_{1} = 2 to get 1+i. The answer is: -1+i , but we can't add this to z_{2} = -3i, since that would give us 1-2i whereas we must get 3. Is there any other way to find out?
The textbook's answer gives f(z) as a linear polynomial with complex coefficients, which is one way to represent this function. It gives the right results for the two given complex numbers.

Edit: Scratch part of what I said. The formula gives the right result for 2 + i, but not the right result for -3i.

Another way to approach this problem is to use linear transformations, and treat complex numbers as vectors in R2.

From the given information, T(2) = T(<2, 0>T) = <1, 1>T, and
T(-3i) = T(<0, -3>T) = <3, 0>T.

Using the properties of linear transformations, it's easy to find T(<1, 0>T) and T(<0, 1>T). That means that you can find T(a + bi) = T(<a, b>T) = aT(<1, 0>T) + bT(<0, 1>T), for any complex number a + bi.
 
Last edited:
I think you mean w2=1. Double check the book. A linear function is f(z)=a*z+b for complex constants a and b. Just put in the given values and solve the two simultaneous equations for a and b.
 
Last edited:
Dick is right. If w2 is 3, then the formula given as an answer is wrong.
 
Dick said:
I think you mean w2=1. Double check the book. A linear function is f(z)=a*z+b for complex constants a and b. Just put in the given values and solve the two simultaneous equations for a and b.

Yes, you're right. w2 is 1, not 3. I'll try to use the method you've given here. Thanks.
 

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