Undergrad Complex Analysis Harmonic functions

Click For Summary
To prove that u(x,y) + cv(x,y) is harmonic, define w(x,y) = u(x,y) + cv(x,y) and calculate wxx + wyy. Since both u and v are harmonic, they satisfy the Laplace equation, meaning Uxx + Uyy = 0 and Vxx + Vyy = 0. By applying the linearity of differentiation, wxx + wyy = Uxx + cVxx + Uyy + cVyy = 0 + c(0) = 0. This confirms that w(x,y) is also harmonic. Understanding the linearity of differentiation is crucial in this proof.
Alvis
Messages
8
Reaction score
1
Suppose u(x,y) and v(x,y) are harmonic on G and c is an element of R. Prove u(x,y) + cv(x,y) is also harmonic.

I tried using the Laplace Equation of Uxx+Uyy=0

I have:
du/dx=Ux
d^2u/dx^2=Uxx

du/dy=Uy
d^2u/dy^2=Uyy

dv/dx=cVx
d^2v/dx^2=cVxx

dv/dy=cVy
d^2v/dy^2=cVyy
I'm not really sure how to prove these are harmonic...am I missing a relationship?
 
Physics news on Phys.org
Define w(x,y) = u(x,y) + cv(x,y) and calculate wxx + wyy. Basic properties of the partial derivative should give you the answer.
 
Wow, that's a really good idea. I was trying to do the harmonic conjugate but was getting nowhere. Thank you!
 
do you understand what it means to say that differentiation is a linear operator?
 
  • Like
Likes FactChecker

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
2K
Replies
3
Views
2K