- #1

RJLiberator

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**The problem states, Show that:**

a) |e^(i*theta)| = 1.

Now, the definition of e^(i*theta) makes this

|cos(theta)+isin(theta)|

If we choose any theta then this should be equal to 1.

What can help me prove this? If I choose, say, pi/6 then it simplifies to |(sqrt(3))/2+i/2)| which doesn't seem to equal 1.

b) BAR(e^(i*theta)) = e^(-i*theta)

Here's what I think. The bar e^(i*theta) means that the definition is cos(theta)-isin(theta) and this can be rewritten as cos(-theta)+i*sin(-theta) which can be inputted back into the definition to see that e^(-i*theta) is correct.