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jaychay
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Given (a,b) is the coordinate just like (x,y). Find equation Zo and coordinate (a,b) ?Please help me
Thank you in advance.
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Can you tell me where does (a,b) = ( 2,1.8 ) come from ?DaalChawal said:Is the answer $z_o = (1,1)$ or simply $1+i$ and $(a, b)=(2, 1.8) $ ? Not sure about b though
We are given the inequality $\operatorname{Re}z\ge b$ and in the graph we can see that the shaded area is to the right of the imaginary axis.jaychay said:I am really struggle with question 2 on how to find (a,b) I am not sure that b = 1.8 is correct or not
So ( a,b ) is equal to ( 2,0 ) right ?Klaas van Aarsen said:We are given the inequality $\operatorname{Re}z\ge b$ and in the graph we can see that the shaded area is to the right of the imaginary axis.
Therefore $b=0$.
Yes.jaychay said:So ( a,b ) is equal to ( 2,0 ) right ?
Sir you are saying that Re(z) = 0 that means z =0 + i y means z will lie on imazinary axis but from the graph z lies in 1st and 4th quadrants except inside the circle. How is this possible?Klaas van Aarsen said:We are given the inequality $\operatorname{Re}z\ge b$ and in the graph we can see that the shaded area is to the right of the imaginary axis.
Therefore $b=0$.
On question one Zo is equal to (1,1) right ?Klaas van Aarsen said:Yes.
We don't have $\operatorname{Re}(z)=0$ for the shaded area. Instead we have $\operatorname{Re}(z)\ge 0$.DaalChawal said:Sir you are saying that Re(z) = 0 that means z =0 + i y means z will lie on imazinary axis but from the graph z lies in 1st and 4th quadrants except inside the circle. How is this possible?
I'd make it $z_0=1+i$, since $z_0$ is an imaginary number.jaychay said:On question one Zo is equal to (1,1) right ?
A complex number equation graph problem is a mathematical problem that involves plotting the solutions of a complex number equation on a graph. Complex numbers are numbers that consist of a real part and an imaginary part, and they are represented as a + bi, where a and b are real numbers and i is the imaginary unit.
To graph a complex number equation, you can plot the real part of the complex number on the x-axis and the imaginary part on the y-axis. The resulting point on the graph represents the solution of the equation. You can also use the distance formula to find the distance between the origin and the point on the graph, which represents the magnitude of the complex number.
Graphing complex number equations can help visualize the solutions of the equation and understand the relationship between the real and imaginary parts. It can also help in solving equations and identifying patterns or trends.
To solve a complex number equation graph problem, you can use algebraic methods such as factoring, completing the square, or the quadratic formula. You can also use graphical methods, such as finding the intersection points of the graph with the x-axis or using the distance formula to find the magnitude of the complex number.
Complex number equation graph problems have many real-life applications, including in engineering, physics, and economics. They can be used to model and analyze systems with both real and imaginary components, such as electrical circuits, mechanical systems, and financial markets.