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I was presented with this problem:

Let z +[itex]\neq -1[/itex] be a complex number with |z|=1.

Show that [itex]\frac{z-1}{z+1}[/itex] is an imaginary number.

I am getting nowhere with the algebra, but i did notiec one thing:

let z=1+0b and the equation says [itex]\frac{z-1}{z+1}[/itex] = [itex]\frac{0}{2}[/itex] = 0, which is not an imaginary number..

Is the problem incorrect?

Thanks!

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# Complex number problem, could the problem be wrong?

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