Complex Trigonometric Solutions

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Bogrune
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Homework Statement


2.) Solve
x7=1
I am to solve for all the solutions to this polynomial, including the complex solutions using trigonometry. I'm supposed to plot my solutions on the unit circle, with the x-axis being the real axis, and the y-axis being the imaginary (or complex) axis.

Homework Equations


I'm supposed to use the following Identities to solve the equation: Rcis, meaning: R (real) times cosine + i(complex) sine.
cisn(θ)=cis(nθ)

The Attempt at a Solution


I've numbered my steps taken in order:

x7=1
1.)(Rcisθ)7=1

2.)Rcis(θ)7=1

3.)cis7(θ)=1

4.)cis(7θ)=1

5.)cos(7θ) + isin(7θ)=1 + i0

5a.) cos(7θ)=1
7θ= cos-1(1)
7θ= 0 + 2πn

5b.) sin(7θ)=0
7θ= sin-1(0)


And that's where I got stuck.
 
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Bogrune said:

I've numbered my steps taken in order:

x7=1
1.)(Rcisθ)7=1

2.)Rcis(θ)7=1

3.)cis7(θ)=1



Do you have a "relevant equation" that explains why you can get rid of the R. (I don't use the cis notation, myself, so I'm not sure what you are supposed to say)

4.)cis(7θ)=1

5.)cos(7θ) + isin(7θ)=1 + i0

5a.) cos(5θ)=1

it should say cos(7θ) , of course

7θ= cos-1(1)
7θ= 0 + 2πn

5b.) sin(7θ)=0
7θ= sin-1(θ)


It should say sin-1(0). (The solution won't add any new information because it will also imply that 7θ= 0 + 2πn


And that's where I got stuck.

Solve 7θ= 0 + 2πn for θ

Let n = 0,1,2... and you'll come back to where you started when n/7 = 1
 
I simply got rid of the "R" because it's not really a variable. I forgot to mention that "R" simply stands for "real", because of the fact that cosθ lies on the x-axis (or the real axis, in this case) and isinθ lies on the y (imaginary)-axis.
And sorry about the typos, I make those pretty often! ^^;
Solve 7θ= 0 + 2πn for θ

Let n = 0,1,2... and you'll come back to where you started when n/7 = 1
Oh, I think I see it now. So I plot those on the unit circle as θ= (0 +2πn)/7, and I get my final solution, right?

Though, thanks for the help!
 
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