Compound Thick Lens: Calculating Refractive Power with Thick Lens Equation

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Homework Statement


I have a compound thick lens problem that I need to find the sign of the refractive power.

Homework Equations


Thick lens equation and focal length equation.

The Attempt at a Solution


I believe all I need to do is calculate the focal length of the first two thick lenses and then use that result as the first "lens" in the same focal length equation again:

##\frac{1}{f_{12}}=\frac{1}{f_{1}}+\frac{1}{f_{2}}-\frac{d_{12}}{f_{1}f_{2}}##
##\frac{1}{f_{123}}=\frac{1}{f_{12}}+\frac{1}{f_{3}}-\frac{d_{123}}{f_{12}f_{3}}##

Is this a correct (or correct enough approximation) to get the sign?
 
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Maybe you could "send in" parallel rays (object at infinity) and try and work out if the image formed by the system is real (+ sign) or virtual (- sign)? What information about the system is available?
 
andrevdh said:
Maybe you could "send in" parallel rays (object at infinity) and try and work out if the image formed by the system is real (+ sign) or virtual (- sign)? What information about the system is available?
I have all the dimensions of the lenses and distances between in the system.
 
HyperPhysics have decent summary of the relevant theory - Gullstrand's equation and principal planes.
 
What 'd' should be used for calculating the power when including the third lens? So I have the first two lenses easy enough. But I'm not sure if I take the P12 to be the distance of the second lens, the average of the distance from 1->3 and 1->2 or just the total distance. I suspect it is the distance from the second lens but I"m not 100% sure.
 
Maybe you should treat each lens separately, otherwise you run into the problem you are now facing - how to locate the second principal plane, which in this instance seems to be "impossible"? Sorry not my forte.
 
Yeah, its been several years since I've had any optics classes so I'm struggling to remember. I recall doing some matrix multiplication for compound lenses but I don't dare delve that deeply. I don't think it is impossible, just more effort.