Compounds undergoing Friedel-Crafts alkylation

  • Context: Chemistry 
  • Thread starter Thread starter jolly_math
  • Start date Start date
  • Tags Tags
    Organic chemistry
Click For Summary
SUMMARY

The 2nd, 3rd, and 6th compounds can undergo Friedel-Crafts alkylation, while the 4th compound cannot. The 4th compound contains an NH2 group, which, in the presence of AlCl3, forms an NH3+ cation that acts as a -M (meta-directing) group, significantly deactivating the compound. In contrast, the 2nd compound has a CH3 group that is activating and allows for successful alkylation. Understanding the role of substituents in Friedel-Crafts reactions is crucial for predicting reactivity.

PREREQUISITES
  • Understanding of Friedel-Crafts alkylation mechanisms
  • Knowledge of activating and deactivating groups in organic chemistry
  • Familiarity with electrophiles and their interactions with nucleophiles
  • Basic concepts of resonance and inductive effects in aromatic compounds
NEXT STEPS
  • Study the role of AlCl3 as a catalyst in Friedel-Crafts reactions
  • Research the effects of different substituents on aromatic reactivity
  • Learn about the differences between activating and deactivating groups
  • Explore examples of Friedel-Crafts alkylation with various substrates
USEFUL FOR

Chemistry students, organic chemists, and anyone studying aromatic substitution reactions will benefit from this discussion.

jolly_math
Messages
51
Reaction score
5
Homework Statement
Which of the following compounds can undergo Friedel-Crafts alkylation?
Relevant Equations
Friedel-Crafts alkylation
1713022840300.png

The answer is that the 2nd, 3rd and 6th compounds can undergo Friedel-Crafts alkylation.

I don't understand why the 4th compound cannot undergo a Friedel-Crafts alkylation reaction, but the 2nd compound can. It has an activating NH2 group and a weakly deactivating Br group, and it's similar to the 2nd compound which has an activating CH3 group and a weakly deactivating Cl group – what makes it different?

Thank you.
 
Physics news on Phys.org
What happens to the NH2 group in the presence of the Friedel-Crafts catalyst?
 
jolly_math said:
Homework Statement: Which of the following compounds can undergo Friedel-Crafts alkylation?
Relevant Equations: Friedel-Crafts alkylation

View attachment 343324
The answer is that the 2nd, 3rd and 6th compounds can undergo Friedel-Crafts alkylation.

I don't understand why the 4th compound cannot undergo a Friedel-Crafts alkylation reaction, but the 2nd compound can. It has an activating NH2 group and a weakly deactivating Br group, and it's similar to the 2nd compound which has an activating CH3 group and a weakly deactivating Cl group – what makes it different?

Thank you.
The thing is the 4th compound has a NH2 group which has a lone pair but in presence of AlCl3 a strong electrophile , the NH2 gives up its lone pair and forms NH3+ cation which is a -M group and highly deactivating, but in the 2nd compound CH3 have activating nature and cannot give any electrons so the chlorine gets removed and CH3 gets added i think
 
PhysicsEnjoyer31415 said:
The thing is the 4th compound has a NH2 group which has a lone pair but in presence of AlCl3 a strong electrophile , the NH2 gives up its lone pair and forms NH3+ cation which is a -M group and highly deactivating, but in the 2nd compound CH3 have activating nature and cannot give any electrons so the chlorine gets removed and CH3 gets added i think
Im sorry but to clarify , not the chlorine on the compound
 

Similar threads

  • · Replies 28 ·
Replies
28
Views
5K
  • · Replies 3 ·
Replies
3
Views
7K
Replies
1
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
Replies
1
Views
12K
  • · Replies 1 ·
Replies
1
Views
13K
  • · Replies 3 ·
Replies
3
Views
8K
  • · Replies 2 ·
Replies
2
Views
8K