Compton Scattering- finding photon wavelength

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SUMMARY

The discussion centers on calculating the wavelength of an incoming photon in a Compton scattering scenario involving an electron moving at relativistic speeds. The initial and final momentum equations are established, incorporating the relativistic momentum formula p=γmv and the energy of the photon Eγ=pc=h/λ. The conservation of momentum and energy principles are applied, leading to the equation h(1/λ + 1/λ') = γfmevef + γimevei. The participants confirm that both momentum and energy are conserved in this interaction, emphasizing the need for accurate expressions for the energy of the electron.

PREREQUISITES
  • Understanding of relativistic momentum (p=γmv)
  • Knowledge of photon energy equations (Eγ=pc=h/λ)
  • Familiarity with conservation laws in physics (momentum and energy conservation)
  • Basic grasp of Compton scattering principles
NEXT STEPS
  • Study the derivation of the Compton wavelength shift formula (λ' - λ = (h/mec)(1-cosθ))
  • Explore relativistic energy equations, specifically E=√(p²c² + m₀²c⁴)
  • Learn about the implications of relativistic speeds on particle interactions
  • Investigate experimental methods for measuring photon wavelengths in scattering experiments
USEFUL FOR

Students and educators in physics, particularly those focusing on particle physics, quantum mechanics, and relativistic phenomena. This discussion is beneficial for anyone studying Compton scattering and its applications in understanding photon interactions with matter.

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Homework Statement


An electron moving to the left at 0.8c collides with an incoming photon moving to the right. After the collision, the electron is moving to the right at 0.6c and an outgoing photon moves to the left. What was the wavelength of the incoming photon?

Homework Equations


p=γmv
Eγ=pc=h/λ

λ'-λ = (h/mec)(1-cosθ)

The Attempt at a Solution


*Defining left as positive*
I have the following expressions for the initial and final momentum of the system, and I set them equal to each other.

Pinitial= pe + pγ
Pi = -γimevei + Eγi/c
Pf = γfmevef - Ef/c

given Ei/c = h/λ

h/λ - γimevei = γfmevef - h/λ'

h(1/λ + 1/λ') = γfmevef + γimevei

I can plug in all the values for the electron and get some number, but I am still left with λ and λ'. I'm not sure if my approach is correct, but if it is, I don't see how I can find just λ (the initial wavelength).
 
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Is the total momentum the only quantity that is conserved?
 
Chandra Prayaga said:
Is the total momentum the only quantity that is conserved?
I presume energy would also be conserved, but writing out that expression also leaves me with λ and λ'

imevi2)/2 +mec2 - hc/λ = hc/λ' - (γfmevf2)/2 - mec2
 
Your expression for the energy of the electron is wrong
 
Would E= √(p2c2 + m02c4) be more accurate?
 
That is correct
 

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