Compton scattering problem - how much did wavelength change by?

Click For Summary
SUMMARY

The discussion focuses on the Compton scattering problem, specifically calculating the change in wavelength of an incident X-ray photon scattered by 30 degrees when interacting with an electron. The relevant equation used is λ' - λ(0) = (h)/(m(e)c) (1 - cos θ), where h is Planck's constant, m(e) is the mass of the electron, and c is the speed of light. The initial calculation yielded a value of 2.424 x 10^-12 m, which was identified as the Compton wavelength of the electron rather than the change in wavelength. The correct interpretation confirms that λ' - λ(0) represents the increase in wavelength after scattering.

PREREQUISITES
  • Understanding of Compton scattering principles
  • Familiarity with the equation λ' - λ(0) = (h)/(m(e)c) (1 - cos θ)
  • Knowledge of Planck's constant, electron mass, and speed of light
  • Basic trigonometry to calculate cosine values
NEXT STEPS
  • Review the derivation of the Compton scattering equation
  • Learn about the implications of wavelength changes in photon interactions
  • Explore the concept of the Compton wavelength and its significance
  • Investigate applications of Compton scattering in modern physics
USEFUL FOR

Students studying quantum mechanics, physicists interested in photon-electron interactions, and educators teaching advanced physics concepts.

daleklama
Messages
33
Reaction score
0

Homework Statement



How much will the wavelength of the incident X-ray photon change by if it is scattered by 30 degrees when it interacts with an electron?

Homework Equations



This is Compton scattering.

This is the equation I used:

lambda ' - lambda (0) = (h)/(m(e)c) (1-cos theta)

where h is Planck's constant, me is the mass of the electron, c is speed of light.

The Attempt at a Solution



Basically I just subbed in everything into the equation above, and got 2.424 x 10^-12 m.

The thing I'm not sure about is whether I'm finished or not.

Does lambda ' minus lambda (0) give me the difference? Did I use the right form of the equation here? Do I need to do anything else?

Thank you :)
 
Physics news on Phys.org
daleklama said:

Homework Statement



How much will the wavelength of the incident X-ray photon change by if it is scattered by 30 degrees when it interacts with an electron?

Homework Equations



This is Compton scattering.

This is the equation I used:

lambda ' - lambda (0) = (h)/(m(e)c) (1-cos theta)

where h is Planck's constant, me is the mass of the electron, c is speed of light.

The Attempt at a Solution



Basically I just subbed in everything into the equation above, and got 2.424 x 10^-12 m.

The thing I'm not sure about is whether I'm finished or not.
You forgot to multiply by the (1 - cos θ) part of the formula. Your value of 2.424 x 10-12 m is just h/(mec), the Compton wavelength of an electron. (And you might want to check the rounding on that too.)
Does lambda ' minus lambda (0) give me the difference?
I'm pretty sure, yes. :approve:

λ' - λ0 represents the increase in wavelength of the photon after scattering, as compared to the wavelength of the original photon. This increase in wavelength is at minimum 0, and at maximum twice the Compton wavelength.
 
Thank you very much, I corrected that :)
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
Replies
13
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 13 ·
Replies
13
Views
7K
Replies
1
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
Replies
1
Views
2K