- #1

- 17

- 2

- Homework Statement
- You have an x-ray source with photon energy of 17 keV and has a spectral distribution which follows a Lorentzian profile with a full width at half maximum of 0.1 eV.

L=L0/(1+2((w-w0)/delta w)^2)

with w=frequency, w0=central frequency (corresponding to the energy, E), delta w=FWHM,L0=1

Show for the Compton formula showing how the spectrum changes

with the detection angle. Show the output graph for theta = 0-180 degrees with an increment

of 5 degrees.

- Relevant Equations
- Compton scattering formula: delta lambda=(h/(m_e*c))(1- cos theta)

First of all, this is question from the modern physics module in 1st year physics program. The problem is I have no prior knowledge about spectroscopy or Lorentzian profile. However, the Compton scattering topic was already introduced.

The Compton scattering formula can be changed into the form:

delta(1/f)=(h/m_e*c^2)(1- cos theta)

The w in the homework statement corresponds to omega.

My question is: How is the spectral distribution related to the Compton scattering? Which variable in the Compton scattering formula corresponds to which variable in the Lorentzian profile? Is the spectral distribution produced by the photons emitted by the electrons after Compton scattering?

And also in the question stated omega is the frequency but normally omega is the symbol of angular frequency, so I am not sure that whether omega is frequency or angular frequency.

Thanks.

The Compton scattering formula can be changed into the form:

delta(1/f)=(h/m_e*c^2)(1- cos theta)

The w in the homework statement corresponds to omega.

My question is: How is the spectral distribution related to the Compton scattering? Which variable in the Compton scattering formula corresponds to which variable in the Lorentzian profile? Is the spectral distribution produced by the photons emitted by the electrons after Compton scattering?

And also in the question stated omega is the frequency but normally omega is the symbol of angular frequency, so I am not sure that whether omega is frequency or angular frequency.

Thanks.