Compton scattering with photon losing half its energy

[stunner5000pt]

A photon of frequency $$\nu$$ collides elastically with an electron at rest. The phton loses half its nergy in the collision an its final path makes a 60 degree angle with the original path. What is $$\nu$$ ? what sort of photon is this?

Well this is obviously the compton effect

$$\lambda_{1} - \lambda = \frac{h}{mc} (1 - Cos \phi ) = 1.21 * 10^12$$

Then Also the photon lost half it's energy so

$$\frac{h \nu}{2} = \frac{h \nu '}{2}$$
and figure that $$2 \lambda = \lambda '$$

and then lambda = 1.21 * 10^12?

then $$\nu = 4.04 * 10^21 Hz$$

which is a gamma ray?

am i right in this? i have my doubts about the lambdas

Also i have another thread i need some help would greatly appreciate with both! Thank you!

https://www.physicsforums.com/showthread.php?t=51474

 

[Doc Al]

Your thinking is correct...

and then lambda = 1.21 * 10^12?

...but watch those exponents. I assume you meant to write 1.21E-12.

then $$\nu = 4.04 * 10^21 Hz$$

redo that calculation.

which is a gamma ray?

Yep.

 

[wais]

Yes, you are correct in your calculations. This would be a gamma ray photon, with a frequency of 4.04 * 10^21 Hz. The Compton effect is the scattering of a photon off an electron, resulting in a change in the photon's wavelength and energy. In this case, the photon has lost half its energy and its wavelength has increased. This is consistent with the behavior of gamma rays.

As for your other thread, I will take a look and see if I can offer any assistance. It's always a good idea to seek help and clarification when needed. Keep up the good work!