Computation time for adiabatic evolution

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SUMMARY

The discussion focuses on the computation time for adiabatic evolution in quantum mechanics, specifically using the adiabatic theorem. The equation for the coefficients is derived, leading to the first-order coefficients' expression. The key result indicates that the computation time must satisfy the condition t << (⟨ψ_m | Ḩ | ψ_m⟩) / (E_n - E_m)². Additionally, the geometric phase, denoted as γ, is clarified as a critical component in the analysis.

PREREQUISITES
  • Understanding of the adiabatic theorem in quantum mechanics
  • Familiarity with perturbation theory
  • Knowledge of quantum state coefficients and eigenstates
  • Basic grasp of geometric phase concepts
NEXT STEPS
  • Study the derivation of the adiabatic theorem in quantum mechanics
  • Explore perturbation theory applications in quantum systems
  • Investigate the geometric phase and its implications in quantum mechanics
  • Learn about the mathematical techniques for evaluating integrals in quantum contexts
USEFUL FOR

Quantum physicists, researchers in quantum mechanics, and students studying adiabatic processes and perturbation theory will benefit from this discussion.

mupsi
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Hi,

my problem: following the adiabatic theorem we get an equation for the coefficients:

<br /> \dot{a}_{m}=-a_{m} \langle{\psi_{m}} | \dot{\psi}_{m}\rangle - \sum_{n \neq m} \frac{\langle \psi_{m} | \dot{H}| \psi_{m}\rangle}{E_{n}-E_{m}} exp(\int_ 0^t E_{n}(t&#039;)-E_{m}(t&#039;) \, dt&#039;)<br />

we start in an eigenstate m. When the gap is large and the time derivative of H is small. We can neglect the sum and get for the coefficient m:

<br /> a_m^0= a_m(0) exp(-i \gamma_m (t))<br />

so far so good. Now we want to determine the 1st order coefficients and make the ansatz:

<br /> a_m= a_m^0 + a_m^1<br />

and we get:

<br /> a_m^1= \sum_{n \neq m} \frac{\langle \psi_{m} | \dot{H}| \psi_{m}\rangle}{(E_{n}-E_{m})^2} a_n^0 exp(\int_ 0^t E_{n}(t&#039;)-E_{m}(t&#039;) \, dt&#039;)<br />

the last step is problematic. It's been a while since I used perturbation theory and I don't know how you get this result. The computation time should be:

<br /> t&lt;&lt;\frac{\langle \psi_{m} | \dot{H}| \psi_{m}\rangle}{(E_{n}-E_{m})^2}<br />

which is clear once you obtain the result above. Can anyone help?
 
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mupsi said:
Hi,

my problem: following the adiabatic theorem we get an equation for the coefficients:

<br /> \dot{a}_{m}=-a_{m} \langle{\psi_{m}} | \dot{\psi}_{m}\rangle - \sum_{n \neq m} \frac{\langle \psi_{m} | \dot{H}| \psi_{m}\rangle}{E_{n}-E_{m}} exp(\int_ 0^t E_{n}(t&#039;)-E_{m}(t&#039;) \, dt&#039;)<br />

we start in an eigenstate m. When the gap is large and the time derivative of H is small. We can neglect the sum and get for the coefficient m:

<br /> a_m^0= a_m(0) exp(-i \gamma_m (t))<br />

so far so good. Now we want to determine the 1st order coefficients and make the ansatz:

<br /> a_m= a_m^0 + a_m^1<br />

and we get:

<br /> a_m^1= \sum_{n \neq m} \frac{\langle \psi_{m} | \dot{H}| \psi_{m}\rangle}{(E_{n}-E_{m})^2} a_n^0 exp(\int_ 0^t E_{n}(t&#039;)-E_{m}(t&#039;) \, dt&#039;)<br />

the last step is problematic. It's been a while since I used perturbation theory and I don't know how you get this result. The computation time should be:

<br /> t&lt;&lt;\frac{\langle \psi_{m} | \dot{H}| \psi_{m}\rangle}{(E_{n}-E_{m})^2}<br />

which is clear once you obtain the result above. Can anyone help?
not sure how to edit posts... a few remarks: it should be t>>... and gamma is the geometric phase.
 

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