Compute Integrals: Integrate (z^3-6z^2+4)dz from -1+i to 1

[asqw121]

Integrate (z^3-6z^2+4)dz where the function is any curve joining -1+i to 1. Z is complex number

 

[MarkFL]

Please post your progress so far so our helpers know exactly where you are stuck or what you may be doing wrong. (Nod)

 

[asqw121]

I am trying to first separate them to integrate individual z^3dz, -6z^2dz and 4dz.

Line integral γ(t)= t*i+(1-t)*(-1-+i)

 

[alyafey22]

There is no need to find a parametric representation of the curve because the function you are integrating has an anti derivative , indeed it is a polynomial . By independence of the path , the integral only depends on the initial and final points .