Computing the moment of inertia for a rotary inverted pendulum

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SUMMARY

The discussion centers on computing the moment of inertia for a rotary inverted pendulum, specifically focusing on the formula for the moment of inertia (J) about the motor shaft. The relevant equation provided is: I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2. Participants emphasize the need for a labeled diagram to clarify the variables involved, including mass and length parameters for the pendulum and arm. The discussion also references previous posts for variable definitions and system parameters.

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Remusco
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Homework Statement
Compute the moment of inertia seen by the motor shaft for a rotary inverted pendulum
Relevant Equations
I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2
I looked all over the internet and I can't find a derivation of this. It is over my head to derive this.
This is my system:
1743111571615.png


I want to assume that the pendulum and motor arm are uniform rods. I want to ignore the motor shaft inertia and the rotary encoder inertia since they are negligible. Does anyone have the formula for J about the motor shaft? I imagine this is dependent on the angle of the pendulum.
 
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Remusco said:
Homework Statement: Compute the moment of inertia seen by the motor shaft for a rotary inverted pendulum
Relevant Equations: I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2

I looked all over the internet and I can't find a derivation of this. It is over my head to derive this.
This is my system:
View attachment 359080

I want to assume that the pendulum and motor arm are uniform rods. I want to ignore the motor shaft inertia and the rotary encoder inertia since they are negligible. Does anyone have the formula for J about the motor shaft? I imagine this is dependent on the angle of the pendulum.
Hi, please wrap your text with Latex tags ##'s.
 
Relevant Equations: ##I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2##

You need to post a labeled diagram of your system. How can we possibly assist if we don't know the meanings of the symbols ##I_m,m_a,l_a,m_p,l_p,\theta_{i-1}##?
 
renormalize said:
Relevant Equations: ##I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2##

You need to post a labeled diagram of your system. How can we possibly assist if we don't know the meanings of the symbols ##I_m,m_a,l_a,m_p,l_p,\theta_{i-1}##?
I assume this is effectively a continuation of https://www.physicsforums.com/threads/simulating-a-rotary-inverted-pendulum-in-python.1079126/
 
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renormalize said:
Relevant Equations: ##I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2##
OK, thanks to @haruspex I've found your previous post that defines most of the variables in your Relevant Equation:
Remusco said:
# System Parameters
m_p = 0.1 # Mass of pendulum (kg)
m_a = 0.5 # Mass of arm (kg)
l_p = 0.2 # Length of pendulum (m)
l_a = 0.15 # Length of arm (m)
g = 9.81 # Gravity (m/s^2)
b = 0.00 # Damping coefficient
I_a = (1/3) * m_a * l_a**2 # Arm moment of inertia
I_p = (1/3) * m_p * l_p**2 # Pendulum moment of inertia
And from the photo of your apparatus in post #1 I surmise that the following is a reasonable representation of your inverted pendulum (but without the Mass at the end of the pendulum rod):
1743140223464.png

(From: https://www.st.com/content/dam/AME/...to_Integrated_Rotary_Inverted_Pendulum_v2.pdf)
If my surmise is correct, can you attempt to write down the formula for the moment-of-inertia ##I_{\text{total}}## seen by the Motor-shaft, in terms of the variables ##r,l,\theta,\phi## shown in Fig. 1 and the masses of the Rotor and Pendulum rods?
 
renormalize said:
OK, thanks to @haruspex I've found your previous post that defines most of the variables in your Relevant Equation:

And from the photo of your apparatus in post #1 I surmise that the following is a reasonable representation of your inverted pendulum (but without the Mass at the end of the pendulum rod):
View attachment 359098
(From: https://www.st.com/content/dam/AME/2019/Educational Curriculums/motor-control/Introduction_to_Integrated_Rotary_Inverted_Pendulum_v2.pdf)
If my surmise is correct, can you attempt to write down the formula for the moment-of-inertia ##I_{\text{total}}## seen by the Motor-shaft, in terms of the variables ##r,l,\theta,\phi## shown in Fig. 1 and the masses of the Rotor and Pendulum rods?
Yes this is what I am looking for. Thanks for clarifying.
 

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