Computing the moment of inertia for a rotary inverted pendulum

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Homework Help Overview

The discussion revolves around computing the moment of inertia for a rotary inverted pendulum system. The original poster describes their setup involving uniform rods for the pendulum and motor arm, while neglecting the inertia of the motor shaft and rotary encoder. They seek the formula for the moment of inertia about the motor shaft, which they believe may depend on the angle of the pendulum.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relevant equations for the moment of inertia and emphasize the need for a labeled diagram to clarify the meanings of various symbols. There is also a suggestion to derive the formula for the moment of inertia in terms of specific variables related to the system.

Discussion Status

The discussion is ongoing, with participants providing insights into the definitions of variables and referencing previous posts for context. Some have expressed the need for additional information, such as a diagram, to facilitate understanding. There appears to be a collaborative effort to clarify the problem and explore the necessary calculations.

Contextual Notes

Participants note the importance of understanding the symbols used in the equations and the original poster's assumptions about the system, including the neglect of certain inertias. There is a reference to a related thread that may provide additional context.

Remusco
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Homework Statement
Compute the moment of inertia seen by the motor shaft for a rotary inverted pendulum
Relevant Equations
I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2
I looked all over the internet and I can't find a derivation of this. It is over my head to derive this.
This is my system:
1743111571615.png


I want to assume that the pendulum and motor arm are uniform rods. I want to ignore the motor shaft inertia and the rotary encoder inertia since they are negligible. Does anyone have the formula for J about the motor shaft? I imagine this is dependent on the angle of the pendulum.
 
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Remusco said:
Homework Statement: Compute the moment of inertia seen by the motor shaft for a rotary inverted pendulum
Relevant Equations: I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2

I looked all over the internet and I can't find a derivation of this. It is over my head to derive this.
This is my system:
View attachment 359080

I want to assume that the pendulum and motor arm are uniform rods. I want to ignore the motor shaft inertia and the rotary encoder inertia since they are negligible. Does anyone have the formula for J about the motor shaft? I imagine this is dependent on the angle of the pendulum.
Hi, please wrap your text with Latex tags ##'s.
 
Relevant Equations: ##I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2##

You need to post a labeled diagram of your system. How can we possibly assist if we don't know the meanings of the symbols ##I_m,m_a,l_a,m_p,l_p,\theta_{i-1}##?
 
renormalize said:
Relevant Equations: ##I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2##

You need to post a labeled diagram of your system. How can we possibly assist if we don't know the meanings of the symbols ##I_m,m_a,l_a,m_p,l_p,\theta_{i-1}##?
I assume this is effectively a continuation of https://www.physicsforums.com/threads/simulating-a-rotary-inverted-pendulum-in-python.1079126/
 
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renormalize said:
Relevant Equations: ##I_{\mathrm{total}}=I_m+\frac{1}{3}m_al_a^2+\frac{1}{3}m_pl_p^2+m_p\left(l_a+\frac{l_p}{2}\cos{\left(\theta_{i-1}\right)}\right)^2##
OK, thanks to @haruspex I've found your previous post that defines most of the variables in your Relevant Equation:
Remusco said:
# System Parameters
m_p = 0.1 # Mass of pendulum (kg)
m_a = 0.5 # Mass of arm (kg)
l_p = 0.2 # Length of pendulum (m)
l_a = 0.15 # Length of arm (m)
g = 9.81 # Gravity (m/s^2)
b = 0.00 # Damping coefficient
I_a = (1/3) * m_a * l_a**2 # Arm moment of inertia
I_p = (1/3) * m_p * l_p**2 # Pendulum moment of inertia
And from the photo of your apparatus in post #1 I surmise that the following is a reasonable representation of your inverted pendulum (but without the Mass at the end of the pendulum rod):
1743140223464.png

(From: https://www.st.com/content/dam/AME/...to_Integrated_Rotary_Inverted_Pendulum_v2.pdf)
If my surmise is correct, can you attempt to write down the formula for the moment-of-inertia ##I_{\text{total}}## seen by the Motor-shaft, in terms of the variables ##r,l,\theta,\phi## shown in Fig. 1 and the masses of the Rotor and Pendulum rods?
 
renormalize said:
OK, thanks to @haruspex I've found your previous post that defines most of the variables in your Relevant Equation:

And from the photo of your apparatus in post #1 I surmise that the following is a reasonable representation of your inverted pendulum (but without the Mass at the end of the pendulum rod):
View attachment 359098
(From: https://www.st.com/content/dam/AME/2019/Educational Curriculums/motor-control/Introduction_to_Integrated_Rotary_Inverted_Pendulum_v2.pdf)
If my surmise is correct, can you attempt to write down the formula for the moment-of-inertia ##I_{\text{total}}## seen by the Motor-shaft, in terms of the variables ##r,l,\theta,\phi## shown in Fig. 1 and the masses of the Rotor and Pendulum rods?
Yes this is what I am looking for. Thanks for clarifying.
 
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