Concave Mirror Image Magnification Calculation

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Homework Help Overview

The discussion revolves around a problem involving a concave mirror with a specified focal length, where participants are tasked with determining the object position that results in an upright image magnified five times. The focus is on understanding the relationships between object distance, image distance, and magnification.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of the magnification equation and the mirror equation, with some questioning the assumptions made about image distance. Others express uncertainty about how to solve for one variable without knowing the other.

Discussion Status

There is ongoing exploration of the relationships between the variables involved. Some participants have suggested methods to express image distance in terms of object distance and magnification, while others are still grappling with the initial setup and assumptions.

Contextual Notes

Participants are working under the constraints of the problem statement, which specifies the focal length and the desired magnification, but does not provide additional information about the image distance or other parameters.

Kris1120
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Homework Statement



A concave mirror has a focal length of
33.5 cm.
Determine the object position for which the
resulting image is upright and five times the
size of the subject.
Answer in units of cm.

Homework Equations



m=-(di/do)

(1/di)+(1/do)= 1/f

The Attempt at a Solution



1/do = (1/35) - (1/5) = -0.170149
do= -5.87719
 
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1/do = (1/35) - (1/5) = -0.170149

You're assuming di is 5 cm here, which isn't true.
 
I don't know how to solve for one without the other?
 
You can write di in terms of do and m (using the magnification equation you had).

Then, substitute that for di in the "1/f=..." equation.
 

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