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Finding image location with concave mirror

  1. Apr 7, 2012 #1
    1. The problem statement, all variables and given/known data
    A small object is located 32.0cm in front of a concave mirror with a radius of curvature of 40.9cm.
    Where will the image be formed?


    2. Relevant equations

    tan(θ)=-h/di
    f=1/2R?

    3. The attempt at a solution

    Haven't been able to solve for theta. I'm not sure what equation to use, but I'm guessing that the radius is important. Do I need to find the focal length?
     
  2. jcsd
  3. Apr 7, 2012 #2

    Redbelly98

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    Welcome to Physics Forums.

    Yes, you need to find the focal length first. And, your text book should have a formula that relates focal length to the positions of the object and image, that will be helpful here.
     
  4. Apr 7, 2012 #3
    you do need to know the focal length. You have to be careful with equations. focal length =R/2 not....1/2R....do you see what I mean/
     
  5. Apr 9, 2012 #4
    Ohhhh, I see. I use 1/do + 1/di = 2/R (which is the focal point, & the reason the difference is indicated). Thank you both!
     
  6. Apr 9, 2012 #5

    Redbelly98

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    Yes, that's the idea. You're welcome!
     
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