Finding image location with concave mirror

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Homework Help Overview

The discussion revolves around determining the image location formed by a concave mirror, given the object's distance and the mirror's radius of curvature. The subject area is optics, specifically the behavior of concave mirrors.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the importance of finding the focal length of the mirror and its relationship to the radius of curvature. There is uncertainty about the correct equations to use and the implications of the focal length in solving the problem.

Discussion Status

Participants have provided guidance on the necessity of calculating the focal length and clarified the correct relationship between the radius of curvature and focal length. There is an ongoing exploration of the relevant equations, with some participants expressing confusion about their formulation.

Contextual Notes

There is a mention of textbook references that may provide additional formulas, indicating that participants are working within the constraints of standard optics principles. The original poster expresses uncertainty about the equations and their application.

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Homework Statement


A small object is located 32.0cm in front of a concave mirror with a radius of curvature of 40.9cm.
Where will the image be formed?


Homework Equations



tan(θ)=-h/di
f=1/2R?

The Attempt at a Solution



Haven't been able to solve for theta. I'm not sure what equation to use, but I'm guessing that the radius is important. Do I need to find the focal length?
 
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Yes, you need to find the focal length first. And, your textbook should have a formula that relates focal length to the positions of the object and image, that will be helpful here.
 
you do need to know the focal length. You have to be careful with equations. focal length =R/2 not...1/2R...do you see what I mean/
 
Ohhhh, I see. I use 1/do + 1/di = 2/R (which is the focal point, & the reason the difference is indicated). Thank you both!
 
Yes, that's the idea. You're welcome!
 

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