Concentration and pressure problem. Need help

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The discussion focuses on the equilibrium of ammonium carbamate (NH2COONH4) at specified conditions. At 442 K, the equilibrium constant (Kc) is 0.043 for the reaction NH2COONH4(s) <=> 2 NH3(g) + CO2(g). When 10.2 g of ammonium carbamate is placed in a 0.500 L container, the total pressure at equilibrium is calculated to be 24.0 atm. Additionally, a second scenario is presented with a Kc of 4.1 at 37 ºC for the same reaction, requiring the concentration of ammonium carbamate in a 0.400 L container.

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Ammonium carbamate (NH2COONH4) is found in the blood and urine of mammals. At a temperature of 442 K, Kc = 0.043 for the following equilibrium:
NH2COONH4(s) <=> 2 NH3(g) + CO2(g).
If 10.2 g of ammonium carbamate is introduced into a 0.500 L container, what is the total pressure inside the container at equilibrium?

Correct answer 2.40E1 (2.40 * 101)

Concentration of NH2COONH4: 0.2613

If someone would help me, I would very much appreciate it.
 
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first write out the equilibrium constant expression
 
Concentration problem. Need help!

Ammonium carbamate (NH2COONH4) is introduced into a 0,4 L container, at a temperature of 37 ºC, Kc = 4,1 for the following equilibrium:
NH2COONH4(s) <=> 2 NH3(g) + CO2(g).
What is total of ammonium carbamate is introduced into a 0.400 L container at equilibrium?
 

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