Concept of Distance and time. (basic question but no answer)

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SUMMARY

The discussion revolves around a physics problem involving two cars, P and Y, approaching a finish line. Car P is 1 km from the finish line, traveling at 35 m/s with a uniform acceleration of 0.4 m/s², while Car Y is 1.2 km away, moving at 44 m/s with an acceleration of 0.5 m/s². The objective is to demonstrate that Car Y overtakes Car P 220 meters before the finish line. The equations of motion used include v² = u² + 2as and s = vt - 1/2at², but the user struggles with the calculations after setting the equations equal.

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Homework Statement


Car P is 1km from finish line with a speed of 35ms-1 and a uniform acceleration of 2/5ms-2
Car Y is 1.2km from finish line going at 44ms-1 and a uniform accelr of 1/2ms-1
show that Y passes p 220m before the finish line.

Homework Equations



v2=u2+2as
s=vt-1/2at^2

The Attempt at a Solution


so the acceleration when they are both in the same position is 0. thus i can use s=vt-1/2at^2 for both and cancel them out. so it would be 220=(44)t-(1/2)(1/2)t^2 for Y and for P it would be 220=(35)t-1/2(2/5)t^2. but then i end up with 0=9t-(1/20)t^2. then what? after that I'm lost.
 
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nabet94 said:
so the acceleration when they are both in the same position is 0.
How did you come up with this?

nabet94 said:
thus i can use s=vt-1/2at^2 for both and cancel them out. so it would be...

Why minus?

The problem states that you have to prove that car Y passes the car P 220 m before the finish line. What is the distance that each car has to pass in order to get to that position, i.e. 220 m before finish line?
 

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