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Conceptual Moment of Inertia Question

  1. Oct 16, 2006 #1
    If I were to attach a sphere (mass M radius R) to the end of a thin rod (mass m length L), the end of the rod being attached to a pivot, how would I calculate the moment of inertia for that object?

    The rod: 1/3 mL^2
    The sphere: 2/5 MR^2

    The object: 1/3 mL^2 +2/5 MR^2 + M(L+R)^2 ???

    Thanks for the help in advance...
  2. jcsd
  3. Oct 16, 2006 #2
    yes, I believe that is correct.
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