Conceptual work/energy question

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SUMMARY

The discussion focuses on the physics of potential and kinetic energy as a person descends two slides of the same height "h," one steeper than the other. It concludes that the horizontal distance from the edge of the slide remains unchanged due to the neglect of friction and air resistance, which are non-conservative forces. The relationship between potential energy (Ep) and kinetic energy (Ek) is maintained, as expressed by the equation v = √(2gh). Thus, the angle of the slide does not affect the energy transformation in this scenario.

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  • Understanding of potential energy and kinetic energy concepts
  • Familiarity with the equation v = √(2gh)
  • Basic knowledge of non-conservative forces in physics
  • Concept of energy conservation in mechanical systems
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  • Explore the effects of friction and air resistance on motion
  • Learn about different types of forces and their classifications
  • Investigate the implications of varying angles on projectile motion
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Homework Statement


Person A is seen going down a slide with height "h". A few seconds later the same person A is seen going down a steeper slide with the same height "h" (same height for both slides). Using principles of physics, explain how the new horizontal distance from the edge of the slide compares with the first situation. Friction and air resistance are negligible.


Homework Equations





The Attempt at a Solution


The conclusion I came to was:

With the new horizontal distance from the edge of the slide, nothing would change because if you neglect the effects of friction and air resistance then that means that you neglect all non-conservative forces and the work done by it. Therefore without any non-conservative forces to effect the system, the change in potential energy would therefore equal the change in kinetic energy (or ΔEp = ΔEk). To sum it up, the steeper slide makes no difference because the only thing that has changed is the angle of the slide.

Would this be correct?
 
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Likes   Reactions: Neha Siddhartha
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Correct.
 
Remember since h remains the same. Ep and Ek are related by [tex]v = \sqrt{2gh}[/tex]
 

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