Condition Number of sum of Matrices

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SUMMARY

The discussion centers on the condition number of the sum of matrices, specifically the hypothesis that cond(A+B) ≤ cond(A) + cond(B). Initial tests in MATLAB suggested this inequality might hold, but further analysis revealed that the hypothesis is incorrect. The participants confirmed that the relationship does not always apply, particularly due to the properties of matrix inverses and norms. The conclusion is that the inequality cond(A+B) ≤ cond(A) + cond(B) is not universally valid.

PREREQUISITES
  • Understanding of matrix norms and condition numbers
  • Familiarity with MATLAB for numerical testing
  • Knowledge of matrix inversion properties
  • Basic linear algebra concepts
NEXT STEPS
  • Research the properties of matrix norms in detail
  • Explore the implications of condition numbers in numerical analysis
  • Learn about matrix addition and its effects on condition numbers
  • Investigate counterexamples to the condition number inequality
USEFUL FOR

Mathematicians, data scientists, and engineers working with numerical methods and matrix computations will benefit from this discussion, particularly those interested in the stability and accuracy of matrix operations.

Abbas
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As far as I know there is no explicit formulas but is this true? I've tested it in Matlab with random matrices and It seems true!
cond(A+B) =< cond(A) + cond(B)
Where can I find a proof for this hypothesis?
 
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I like Serena said:
Welcome to MHB, Abbas! :)

\begin{aligned}
\text{cond}(A+B)
&= ||(A+B)^{-1}|| \cdot ||A+B|| \\
&= ||A^{-1} + B^{-1}||\cdot ||A+B|| \\
&\le \Big(||A^{-1}||+||B^{-1}||\Big) \cdot \Big(||A||+||B||\Big) \\
&\le ||A^{-1}||\cdot||A|| + ||B^{-1}||\cdot||B|| \\
&= \text{cond}(A) + \text{cond}(B)
\end{aligned}

Thanks, but Are you sure if this is true?
I doubt (A+B)-1= A-1+B-1.
How about ||A-1||⋅||B||+||A||⋅||B-1|| ? can these terms be omitted?
 
Abbas said:
Thanks, but Are you sure if this is true?
I doubt (A+B)-1= A-1+B-1.
How about ||A-1||⋅||B||+||A||⋅||B-1|| ? can these terms be omitted?

You're quite right. I had just deleted my post, since I realized it was not correct due to the very reasons you mention.
 
I like Serena said:
You're quite right. I had just deleted my post, since I realized it was not correct due to the very reasons you mention.

I was looking for an answer since I post it here, cond(A+B) =< cond(A) + cond(B) is not always true. the hypothesis is wrong. Thanks BTW. :)
 

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