- #1
sampahmel
- 21
- 0
Dear all,
P (A |B) + P (A c|B) = 1 [A c] denotes complement of set A and of course P (B)>0
Is the above statement true?
How about the following two:
P (A |B) + P (A |B c) = 1
P (C ∪ D|B) = P (C |B) + P (D|B) − P (C ∩ D|B)
P (A |B) + P (A c|B) = 1 [A c] denotes complement of set A and of course P (B)>0
Is the above statement true?
How about the following two:
P (A |B) + P (A |B c) = 1
P (C ∪ D|B) = P (C |B) + P (D|B) − P (C ∩ D|B)