Conformal Mapping Homework: f(z) = 1/(z-1), c=i

Click For Summary
SUMMARY

The discussion focuses on the analysis of the function f(z) = 1/(z-1) at the point c = i, specifically examining its infinitesimal behavior using the conformal mapping theorem. The derivative f'(c) is calculated as -1/(z-1)^2, which evaluates to 1/2i, indicating a scaling effect on the imaginary axis. The conformal mapping theorem states that if f is analytic in the disc |z-z0| PREREQUISITES

  • Understanding of complex functions and their derivatives
  • Familiarity with the concept of conformal mapping
  • Knowledge of polar coordinates and the argument of complex numbers
  • Basic calculus, specifically differentiation
NEXT STEPS
  • Study the implications of the conformal mapping theorem in complex analysis
  • Learn how to compute the argument of complex numbers in various contexts
  • Explore the geometric interpretation of derivatives in complex functions
  • Investigate applications of conformal mappings in fluid dynamics and engineering
USEFUL FOR

Students of complex analysis, mathematicians focusing on conformal mappings, and anyone interested in the geometric properties of complex functions.

desaila
Messages
25
Reaction score
0

Homework Statement



"Study the infinitesimal behavior of f at the point c. (In other words, use the conformal mapping theorem to describe what is happening to the tangent vector of a smooth curve passing through c.)"

f(z) = 1/(z-1), c=i

Homework Equations



|f'(c)| and arg f'(c)


The Attempt at a Solution



I know what |f'(c)| is, d/dz is -1/(z-1)^2, and evaluates out to 1/2i. However, I'm not sure what exactly that's saying about the behavior. Does it mean it's shrinking on the imaginary axis by 1/2 ?

Also, about the argument... this is something I can't quite wrap my head around. I've read in this math text, and the wiki entry on arguments, but I'm not quite sure I get it. The equation in this book is, the argument of z = |z|(cos(theta)+ i*sin(theta)) where |z| = sqrt(x^2+y^2).

Thanks.
 
Physics news on Phys.org
Since the problem specifically says "use the conformal mapping theorem", what is the conformal mapping theorem and how does it apply to this problem?

I very much doubt that your book says that the "argument" of x. If z= a+ bi, in polar form is [itex]r (cos(\theta)+ i sin(\theta))= re^{i\theta}[/itex] then the "modulus" of z is [itex]r= \sqrt{a^2+ b^2}[/itex] and the "argument" of z is [itex]\theta= arctan(b/a)[/itex]. By the time you are working with "conformal mapping", that should be old stuff.
 
It is old stuff, but I didn't quite understand it then. The conformal mapping theorem, according to the book, is, "If f is analytic in the disc |z-zo|<r and if f'(zo) != 0, then f is conformal at zo."

Where zo is z with subscript 0.
 

Similar threads

Replies
7
Views
3K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 25 ·
Replies
25
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
2
Views
2K