The discussion revolves around interpreting a solution provided by Wolfram Alpha for an equation involving the variable theta. The original poster expresses confusion regarding the meaning of the solution, which includes a term for integer n, and seeks clarification on whether theta should be converted to degrees.
Some participants provide guidance on the interpretation of the solution, noting that Wolfram Alpha's output is in radians and confirming the correctness of the conversion method. The discussion includes an exploration of the implications of n being any integer, indicating the presence of multiple solutions without reaching a consensus on specific values.
Participants discuss the nature of the equation being solved and the assumptions regarding the variable theta, including the consideration of both positive and negative multiples of 2π.
That would be one value, with n = 0. The other values are .74559 + 2##\pi##, .74559 + 4##\pi##, .74559 + 6##\pi##, and so on. It would also include negative multiples of 2##\pi##, as in .74559 - 2##\pi##, .74559 - 4##\pi##, .74559 - 6##\pi##, and so on.Clever_name said:Homework Statement
Ok well I had a real nasty equation in which i could not solve.
I used wolfram alpha to get out this answer "theta ≈ 0.74559 + 6.28319n for integer n".
can someone please tell me what this statement means.
do i assume theta in degrees equals 0.74559(180/pi)?
n is any integer. You can't say what it "is." It means that the equation has multiple solutions.Clever_name said:So if i was solving an equation say something like x'(theta) =0 would n be zero when solving for theta?