Confused about +- symbol use in inverse function

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The discussion centers on the use of the ± symbol in the context of inverse functions, specifically in the equation y = ±√(x + 4). The necessity of the ± symbol arises because both positive and negative values of y can satisfy the equation when x = 0, leading to y being either +2 or -2. Participants clarify that taking the square root of a number yields two possible values, as both positive and negative roots will square to the same result. Additionally, it is noted that the original function does not have an inverse since it is not one-to-one, meaning multiple x values can correspond to the same y value. Understanding this concept is crucial for correctly applying the ± symbol in similar mathematical contexts.
priceofcarrot
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Hi, so this isn't a question, it's just an example that they've given, but I don't understand the explanation given.


You have :

y = x^2 - 4
x = y^2 - 4
y^2 = x + 4
y = ± sqrt(x+4)


I don't get why there is a ± symbol there. My book says that it's necessary because there are two values for y that will satisfy the equation, and that if x = 0, y could be +2 or -2.


I understand that y could = +2, because sqrt 4 = +2, but I don't see how it could equal -2.

How would I know that I should include the ± symbol in front of the sqrt(x+4)? Thanks
 
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priceofcarrot said:
Hi, so this isn't a question, it's just an example that they've given, but I don't understand the explanation given.


You have :

y = x^2 - 4
x = y^2 - 4
y^2 = x + 4
y = ± sqrt(x+4)


I don't get why there is a ± symbol there. My book says that it's necessary because there are two values for y that will satisfy the equation, and that if x = 0, y could be +2 or -2.


I understand that y could = +2, because sqrt 4 = +2, but I don't see how it could equal -2.

How would I know that I should include the ± symbol in front of the sqrt(x+4)? Thanks

What is (-2)*(-2)?

RGV
 
Whenever you take the square root of something it requires a +or- because the square of either the negative or positive value of that term would yield the same number when it is squared. for instance (-x)^2=(x)^2

since you are squaring y, you must be aware that the sqrt of (x+4) will net y regardless if it is positive or negative
 
AHHHH! I get it.

This forum rocks, thanks!
 
priceofcarrot said:
AHHHH! I get it.

This forum rocks, thanks!

indeed it does
 
Note, by the way, that what this is saying is that the original function does NOT HAVE an inverse! A function has an inverse if and only if it is "one to one". That is, there is only one value of x that gives a specific y value. It that is not true, we can choose a specific one of the x values for a given y value, as here choosing "+" or "-", which is equivalent to choosing a subset of the original function.
 
priceofcarrot said:

Homework Statement


Homework Equations


The Attempt at a Solution



Hi, so this isn't a question, it's just an example that they've given, but I don't understand the explanation given.You have :

y = x^2 - 4
x = y^2 - 4
y^2 = x + 4
y = ± sqrt(x+4)I don't get why there is a ± symbol there. My book says that it's necessary because there are two values for y that will satisfy the equation, and that if x = 0, y could be +2 or -2. I understand that y could = +2, because sqrt 4 = +2, but I don't see how it could equal -2.

How would I know that I should include the ± symbol in front of the sqrt(x+4)? Thanks

For example, if you have ##p^2=2##, then ##p=\pm\sqrt2##. Same thing here.
 
Last edited:
dimension10 said:
For example, if you have ##p^2=2##, then ##p=\pm2##. Same thing here.

±√2 that is
 
AmritpalS said:
±√2 that is
Oops, sorry about that. Editted.
 

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