Confusion about how KCL and KVL are used for diode circuits

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SUMMARY

The discussion centers on the application of Kirchhoff's Current Law (KCL) and Kirchhoff's Voltage Law (KVL) in analyzing diode circuits, specifically when using the constant voltage model for diodes. The user expresses confusion regarding the behavior of current in the presence of a diode, particularly when it is assumed to be in the "on" state, leading to the interpretation of the diode as a short circuit. The resolution involves understanding that while the diode is modeled as a short circuit, the presence of other components, such as resistors, still allows for current flow in parallel branches.

PREREQUISITES
  • Understanding of Kirchhoff's Current Law (KCL)
  • Understanding of Kirchhoff's Voltage Law (KVL)
  • Familiarity with diode operation and characteristics
  • Knowledge of the constant voltage model for diodes
NEXT STEPS
  • Study the constant voltage model for diodes in circuit analysis
  • Learn about the implications of ideal vs. non-ideal diode behavior
  • Explore advanced applications of KCL and KVL in complex circuits
  • Review examples of diode circuits in textbooks or online resources
USEFUL FOR

Electrical engineering students, circuit designers, and anyone seeking to deepen their understanding of diode behavior in circuit analysis.

timnswede
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Homework Statement


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This is just one of the example problems in my book which is already solved for me, but I don't really understand their solution which I'll post here:
They start out with assuming Vin is very negative, which makes D1 turn on and makes Vout=VD,on+Vin. THen they solve for the currents.
JYPhFsY.png

Homework Equations


KCL/KVL

The Attempt at a Solution


What I am confused on is that if the diode is turned on, then the branch with the diode is a short circuit, so why is there current going in the R2 branch?
The book solves all the problems like this one the same way, but I don't really get it. Are we assuming the diode is actually on the brink of turning on/off, so it allows current through it, but it's actually not a short circuit yet?
 
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timnswede said:
What I am confused on is that if the diode is turned on, then the branch with the diode is a short circuit, so why is there current going in the R2 branch?
What does VD.on represent? Is the diode treated as ideal or non-ideal in these problems? :wink:
 
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timnswede said:
if the diode is turned on, then the branch with the diode is a short circuit,
No. You are asked to use the constant voltage model for the diode.
images (4).jpg
 
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Oh wow, not sure why I didn't realize it until you guys said it, but now it makes sense, thanks!
 

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