Confusion about how KCL and KVL are used for diode circuits

  • #1
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Homework Statement


Eo5OrNh.png

This is just one of the example problems in my book which is already solved for me, but I don't really understand their solution which I'll post here:
They start out with assuming Vin is very negative, which makes D1 turn on and makes Vout=VD,on+Vin. THen they solve for the currents.
JYPhFsY.png



Homework Equations


KCL/KVL

The Attempt at a Solution


What I am confused on is that if the diode is turned on, then the branch with the diode is a short circuit, so why is there current going in the R2 branch?
The book solves all the problems like this one the same way, but I don't really get it. Are we assuming the diode is actually on the brink of turning on/off, so it allows current through it, but it's actually not a short circuit yet?
 

Answers and Replies

  • #2
gneill
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What I am confused on is that if the diode is turned on, then the branch with the diode is a short circuit, so why is there current going in the R2 branch?
What does VD.on represent? Is the diode treated as ideal or non-ideal in these problems? :wink:
 
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  • #3
cnh1995
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if the diode is turned on, then the branch with the diode is a short circuit,
No. You are asked to use the constant voltage model for the diode.
images (4).jpg
 
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  • #4
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Oh wow, not sure why I didn't realize it until you guys said it, but now it makes sense, thanks!
 

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