Confusion about how KCL and KVL are used for diode circuits

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Homework Help Overview

The discussion revolves around the application of Kirchhoff's Current Law (KCL) and Kirchhoff's Voltage Law (KVL) in the context of diode circuits. The original poster expresses confusion regarding the behavior of a diode when it is assumed to be in the 'on' state and its implications for current flow in associated branches.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of treating the diode as a short circuit versus using a constant voltage model. Questions are raised about the meaning of the diode's forward voltage drop and whether the diode is considered ideal or non-ideal in the context of the problem.

Discussion Status

The discussion has led to some clarification regarding the assumptions made about the diode's behavior. Participants are engaging with the concepts and questioning the standard approaches used in the textbook examples, indicating a productive exploration of the topic.

Contextual Notes

There is an indication that the original poster is working from a textbook example, which may impose certain assumptions about the diode's characteristics that are being critically examined in the discussion.

timnswede
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Homework Statement


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This is just one of the example problems in my book which is already solved for me, but I don't really understand their solution which I'll post here:
They start out with assuming Vin is very negative, which makes D1 turn on and makes Vout=VD,on+Vin. THen they solve for the currents.
JYPhFsY.png

Homework Equations


KCL/KVL

The Attempt at a Solution


What I am confused on is that if the diode is turned on, then the branch with the diode is a short circuit, so why is there current going in the R2 branch?
The book solves all the problems like this one the same way, but I don't really get it. Are we assuming the diode is actually on the brink of turning on/off, so it allows current through it, but it's actually not a short circuit yet?
 
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timnswede said:
What I am confused on is that if the diode is turned on, then the branch with the diode is a short circuit, so why is there current going in the R2 branch?
What does VD.on represent? Is the diode treated as ideal or non-ideal in these problems? :wink:
 
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timnswede said:
if the diode is turned on, then the branch with the diode is a short circuit,
No. You are asked to use the constant voltage model for the diode.
images (4).jpg
 
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Oh wow, not sure why I didn't realize it until you guys said it, but now it makes sense, thanks!
 

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