Confusion about the boundary of a simple set

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Homework Help Overview

The discussion revolves around determining the boundary of a set defined by the inequality 0<|z-z0|<2, where z=(x,y). Participants are examining the interpretation of the boundary in relation to the points included in the set.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are questioning the book's solution, which states that the boundary includes the circle |z-z0|=2 and the point (0,0). There is confusion about whether z0 should also be included as part of the boundary.

Discussion Status

Some participants express uncertainty about the correctness of the book's answer, suggesting that it may not accurately represent the boundary as defined by the original inequality. There is an acknowledgment of potential typographical errors in the book's solution.

Contextual Notes

One participant notes that this is their first exposure to these concepts, indicating a learning context where foundational understanding is being developed.

Nathanael
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Homework Statement



Determine the boundary of the following set. As usual, z=(x,y).

[itex]0<\left| z-z_0 \right|<2[/itex]

2. The attempt at a solution

The book's solution says "The circle [itex]\left| z-z_0 \right|=2[/itex] together with the point (0,0)"

Why should the answer not be "... together with the point [itex]z_0[/itex]"?
 
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Nathanael said:

Homework Statement



Determine the boundary of the following set. As usual, z=(x,y).

[itex]0<\left| z-z_0 \right|<2[/itex]

2. The attempt at a solution

The book's solution says "The circle [itex]\left| z-z_0 \right|=2[/itex] together with the point (0,0)"

Why should the answer not be "... together with the point [itex]z_0[/itex]"?
The book's answer seems incorrect to me. The original inequality represents all of the points inside (but not on) the circle of radius 2 with center at z0, not including this center point.
 
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Nathanael said:

Homework Statement



Determine the boundary of the following set. As usual, z=(x,y).

[itex]0<\left| z-z_0 \right|<2[/itex]

2. The attempt at a solution

The book's solution says "The circle [itex]\left| z-z_0 \right|=2[/itex] together with the point (0,0)"

Why should the answer not be "... together with the point [itex]z_0[/itex]"?
Yes, that was clearly a typo.
 
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Thank you both, it's my first time learning these ideas (even if they are fairly simple) so I just wanted to make sure I wasn't misunderstanding.
 

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