Conjugate fields and conjugate subgroups of an automorphism group

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SUMMARY

Conjugate fields E and D over a field F are established as equivalent if and only if their corresponding Galois groups G and H, which are subgroups of the automorphism group Aut(K/F), are conjugate subgroups. The discussion emphasizes that the Galois closure K is the field fixed by the core of Aut(D/F) and Aut(E/F), although the definition of "core" requires clarification due to the lack of a defined overarching group. The precise definition of conjugate fields is essential for resolving these questions.

PREREQUISITES
  • Understanding of Galois theory and finite field extensions
  • Familiarity with automorphism groups, specifically Aut(K/F)
  • Knowledge of conjugate fields and their properties
  • Concept of the core of a group and its significance in group theory
NEXT STEPS
  • Study the definition and properties of conjugate fields in Galois theory
  • Explore the structure and significance of the automorphism group Aut(K/F)
  • Investigate the concept of the core of a group and its applications
  • Learn about Galois closures and their relationship with finite extensions
USEFUL FOR

Mathematicians, particularly those specializing in algebra and Galois theory, as well as students seeking to deepen their understanding of field extensions and automorphism groups.

imurme8
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Suppose E and D are both finite extensions of F, with K being the Galois closure of \langle D,E \rangle (is this the correct way to say it?) Is it correct that E and D are conjugate fields over F iff G,H are conjugate subgroups, where G,H\leqslant \text{Aut}(K/F) are the subgroups which fix E,D?

I want to claim also that given E,D, we have that their Galois closure K is exactly the field fixed by the core of \text{Aut}(D/F) and \text{Aut}(E/F), but I'm not sure if the "core" is well-defined in this case, since we've not defined a group of which \text{Aut}(D/F) and \text{Aut}(E/F) are a subgroup. What do you think?
 
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what is the definition of conjugate fields? if you give it precisely maybe you can answer your own question.
 

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