Connecting two charged capacitors

  • Thread starter Thread starter Eitan Levy
  • Start date Start date
  • Tags Tags
    Capacitors Charged
Click For Summary

Homework Help Overview

The problem involves two capacitors, one with a capacitance of 6μF and another with 12μF, which are initially charged in series to a voltage of 660V. The discussion focuses on determining the charge and voltage of each capacitor after they are disconnected from the voltage source and connected to each other in two different configurations.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of total capacitance for capacitors in series and how to apply the formula Q=CV to find charge. There is uncertainty about how to proceed after the capacitors are connected to each other in different configurations, particularly regarding the equalization of potentials and charges.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the calculation of total capacitance and charge, but there remains uncertainty about the subsequent steps after the capacitors are connected to each other.

Contextual Notes

Participants express confusion about the calculations required after the capacitors are connected in various ways, indicating a need for clarification on the assumptions regarding charge distribution and potential equalization.

Eitan Levy
Messages
259
Reaction score
11

Homework Statement


One capacitor with a capacity of 6μF and another with a capacity of 12μF are charged by being connected in a series to a voltage source with an electrive force of 660V. After that, we disconnect the capacitors from the source and connect them to each other.
What is the charge and the voltage of each capacitor if we connect each positive plate to the other's positive plate?
What is the charge and the voltage of each capacitor if we connect each positive plate to the other's negative plate?

Homework Equations


Q=CV

The Attempt at a Solution


In the first case I think that the potentials will be equal, but I am still not sure how to calculate this. In the second case the charges will be equal, but again, I can't figure how to calculate it.
 
Physics news on Phys.org
You wrote that the capacitor are connected in series, so to calculate the total capacity you can use the formula: 1/Ctot= (1/C1 + 1/C2)
Once you find Ctot you can use it in the Q=CV formula and calculate the charge, because you have to total voltage that is 660V.
 
Grands said:
You wrote that the capacitor are connected in series, so to calculate the total capacity you can use the formula: 1/Ctot= (1/C1 + 1/C2)
Once you find Ctot you can use it in the Q=CV formula and calculate the charge, because you have to total voltage that is 660V.
This is the part that I knew what to do in, I don't what to do after the capacitors are connected to each other in each case.
 
Eitan Levy said:
What is the charge and the voltage of each capacitor if we connect each positive plate to the other's positive plate?
What is the charge and the voltage of each capacitor if we connect each positive plate to the other's negative plate?

. The attempt at a solution
In the first case I think that the potentials will be equal, but I am still not sure how to calculate this. In the second case the charges will be equal, but again, I can't figure how to calculate it.

I think I would not calculate anything, I would just draw a picture. What are you putting in contact with what, and what are the charges going to do?
 

Similar threads

Replies
4
Views
2K
  • · Replies 18 ·
Replies
18
Views
3K
Replies
11
Views
4K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 12 ·
Replies
12
Views
5K
Replies
3
Views
2K
Replies
1
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
1K