Consecutive and minimum pair puzzle

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    Minimum Pair Puzzle
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SUMMARY

The discussion focuses on finding two consecutive positive decimal integers whose digit sums are divisible by 11. The minimum pair identified is 2899999 and 2900000. The analysis reveals that for n 9's, the condition 9*n-1 must be divisible by 11, leading to the conclusion that n equals 5. The digit sum of the first number is calculated to be 10, confirming the validity of the pair.

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K Sengupta
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Two consecutive positive decimal integers are such that the sum of the digits of each of them is divisible by 11.

Determine the minimum possible pair of such numbers.
 
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Let the 2 numbers be:
t...x y z 99...9
and
t...x y (z+1) 00...0

Suppose n 9's.
Then 9*n-1 is divisible by 11.
So, n=5.
We know the first number is
t...x y z 99999
But t+...+x+y+z = 55-45=10. So, the numbers are
2899999 and 2900000

:smile:
 

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