Conservation of Angular and Linear Momentum

Click For Summary
In the discussion on conservation of angular and linear momentum, it is established that only angular momentum is conserved when a student jumps off a frictionless circular platform. The reason linear momentum is not conserved is due to the external force exerted by the platform's axle, which is fixed to the ground. If the platform were free to move, both linear and angular momentum would be conserved. The conservation of angular momentum is specific to the reference point of the axle, as it affects the system's dynamics. Understanding these principles clarifies the confusion regarding the conservation laws in this scenario.
Jzhang27143
Messages
38
Reaction score
1

Homework Statement



A student initially stands on a circular platform that is free to rotate without friction about its center. The student jumps off tangentially, setting the platform spinning. Quantities that are conserved for the student-platform system as the student jumps include which of the following?

I. Linear Momentum
II. Angular Momentum
III. Kinetic Energy

Homework Equations



F = dp/dt, T = dl/dt

The Attempt at a Solution



The answer is only angular momentum. However, I do not understand why angular momentum is conserved but not linear momentum. Since the system consists of the student and the platform, the force of the student on the platform and the reaction force are internal forces. They don't contribute to external force or torque. Am I missing something?
 
Physics news on Phys.org
Jzhang27143 said:

Homework Statement



A student initially stands on a circular platform that is free to rotate without friction about its center. The student jumps off tangentially, setting the platform spinning. Quantities that are conserved for the student-platform system as the student jumps include which of the following?

I. Linear Momentum
II. Angular Momentum
III. Kinetic Energy

Homework Equations



F = dp/dt, T = dl/dt

The Attempt at a Solution



The answer is only angular momentum. However, I do not understand why angular momentum is conserved but not linear momentum. Since the system consists of the student and the platform, the force of the student on the platform and the reaction force are internal forces. They don't contribute to external force or torque. Am I missing something?
If the platform were completely free to move, both would be conserved. But the center of the platform apparently doesn't move.
 
  • Like
Likes 1 person
Jzhang27143 said:
Am I missing something?
You are missing the external force from the platform's axle, which is presumably attached to the ground. If it wasn't fixed in place, then linear momentum would be conserved.
 
  • Like
Likes 1 person
The question isn't quite right, and that may lead to your confusion.
Angular momentum is only meaningful in terms of some reference point. In the present case, the question assumes that reference point is the axle of the platform. If you were to take any other reference point it would not be conserved.
Given the answers by Doc Al and SammyS, do you see why the axle is special here?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

Replies
2
Views
1K
Replies
17
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 17 ·
Replies
17
Views
878
  • · Replies 6 ·
Replies
6
Views
2K
Replies
26
Views
1K
  • · Replies 12 ·
Replies
12
Views
2K
Replies
335
Views
16K