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## Homework Statement

On a frictionless table, a glob of clay of mass 0.380 kg strikes a bar of mass 0.9 kg perpendicularly at a point 0.550 m from the center of the bar and sticks to it.

a) a) If the bar is 1.300 m long and the clay is moving at 8.100 m/s before striking the bar, what is the final speed of the center of mass? (Got this, 2.405m/s)

b)At what angular speed does the bar/clay system rotate about its center of mass after the impact (in rad/s)?

## Homework Equations

L

_{i}=L

_{f}

L=r x p =mrv (when theta = 90, as in this case)

L=Iw

I of a rod = (ML

^{2})/12

x

_{center of mass}=Ʃmx/Ʃm

## The Attempt at a Solution

m = mass of clay

M=mass of bar

u=clay's initial speed

r=the distance from the clay to the new CM

So I set one end of the bar as x=0 and the other as x=1.3 to calculate CM

CM=((0.38)(0.65+0.55)+(0.65)(0.9))/(0.9+0.38)=0.81328m from the end of the bar

r=1.2-0.81328=0.3867m

Initial angular velocity=mru

Final " "=((1/12)ML

^{2}+mr

^{2})ω

so ω=(mru)/((1/12)(ML

^{2}+mr

^{2})

When I plug in my values, I get the wrong answer, it is supposed to be 5.73. Where am I going wrong? I have spent hours at this :( I'm so frustrated!

## Homework Statement

## Homework Equations

## The Attempt at a Solution

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