Conservation of Energy and Momentum

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SUMMARY

The discussion focuses on the conservation of energy and momentum in a physics problem involving a swinging mass. The key equation presented is V = Sqrt(2gh), which calculates the velocity of the mass at the bottom of the swing. Participants debated the relationship between angular momentum and linear momentum, specifically questioning if the angular momentum of mass B equals the linear momentum of mass B. The necessity of a fixed pivot point for the application of these principles was also highlighted.

PREREQUISITES
  • Understanding of basic physics concepts such as energy conservation and momentum.
  • Familiarity with the equation for gravitational potential energy: PE = mgh.
  • Knowledge of angular momentum and its relation to linear momentum.
  • Ability to apply kinematic equations in a physics context.
NEXT STEPS
  • Study the principles of conservation of angular momentum in dynamic systems.
  • Learn how to derive linear velocity from potential energy equations.
  • Explore the effects of pivot points on momentum calculations.
  • Investigate real-world applications of energy conservation in mechanical systems.
USEFUL FOR

Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of energy and momentum conservation in dynamic systems.

nonaJ
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Homework Statement


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Homework Equations

The Attempt at a Solution


I know that the velocity of mass at the bottom of the swing is
V = Sqrt(2gh), but I'm not sure how to get from there to the velocity of A. Is it as simple as Angular momentum of B = Linear Momentum of B?
 
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nonaJ said:
I know that the velocity of mass at the bottom of the swing is
V = Sqrt(2gh),
That would be true if the pivot were fixed.

What are your answers to parts a and b? (Those are the keys to solving c.)
 

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