# Conservation of energy - elastic potential energy and k.e.

1. Homework Statement

For part (iii) , I used the principle of conservation of energy,
K.E of the 2 kg particle after collision + E.P.E = K.E of the 2 kg particle at the furthest distance away from A + E.PE,

But the solution for this question did not include the E.P.E of the string after collision (in bold), why? Shouldn't there still be tension in the string?

haruspex
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1. Homework Statement
View attachment 97599
For part (iii) , I used the principle of conservation of energy,
K.E of the 2 kg particle after collision + E.P.E = K.E of the 2 kg particle at the furthest distance away from A + E.PE,

But the solution for this question did not include the E.P.E of the string after collision (in bold), why? Shouldn't there still be tension in the string?
Based on the information you have provided, I would agree with you. But this leaves the possibility that you have misunderstood something in the solution provided and therefore not portrayed it accurately.
As a way of checking, what answer did you get and what answer does the book get?

Based on the information you have provided, I would agree with you. But this leaves the possibility that you have misunderstood something in the solution provided and therefore not portrayed it accurately.
As a way of checking, what answer did you get and what answer does the book get?

I did this :
1/2 (2)(0)2 +1/2 (72) (x)2 = 1/2 (2) (4)2 + 1/2 (72)(1)2

haruspex