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Conservation of energy - elastic potential energy and k.e.

  1. Mar 19, 2016 #1
    1. The problem statement, all variables and given/known data
    image.jpg
    For part (iii) , I used the principle of conservation of energy,
    K.E of the 2 kg particle after collision + E.P.E = K.E of the 2 kg particle at the furthest distance away from A + E.PE,

    But the solution for this question did not include the E.P.E of the string after collision (in bold), why? Shouldn't there still be tension in the string?
     
  2. jcsd
  3. Mar 19, 2016 #2

    haruspex

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    Based on the information you have provided, I would agree with you. But this leaves the possibility that you have misunderstood something in the solution provided and therefore not portrayed it accurately.
    As a way of checking, what answer did you get and what answer does the book get?
     
  4. Mar 20, 2016 #3
    image.jpg

    I did this :
    1/2 (2)(0)2 +1/2 (72) (x)2 = 1/2 (2) (4)2 + 1/2 (72)(1)2
     
  5. Mar 20, 2016 #4

    haruspex

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    I agree with your equation.
    I note that the wrong solution is monospaced type, as from an old typewriter, whereas the problem statement is a page from a book.
     
  6. Mar 20, 2016 #5
    Yeah it is
    Thanks for your help !
     
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