# Conservation of Energy find the speed of the blocks

## Homework Statement

In the figure the second block slides horizontally without friction while the first block falls. Use the Conservation of Energy to find the speed of the blocks after they have moved 2 meters, starting from rest. The falling block has mass 3 kg, the sliding block has mass 5 kg, and the pulley is ideal.
See Figure 1.

## Homework Equations

Uf + Kf = Ui + Ki

## The Attempt at a Solution

So for the 3 kg block:
mghf = 1/2mvf2 = mghi + 1/2mvi2
(3 kg)(9.8 m/s2)(2 m) + 1/2(3 kg)(vf)2 = 0
1/2(3 kg)(vf)2 = 58.8 J
(vf)2 = 39.2 m2/s2
vf = 6.26 m/s

I'm not sure if I quite got the point of the conservation of energy bit. Does it mean the work done by the pulley is zero? That's what I had to assume to get vf for the 3 kg block. I'm not sure what to do about the 5 kg block, though, because if I just use 2 m for the h for it, then I get the same vf as the 3 kg block, which seems odd to me. But maybe I'm missing the point.

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