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Homework Help: Conservation of Energy max height

  1. Feb 24, 2008 #1
    1. The problem statement, all variables and given/known data
    An arrow(mass=0.2kg) is fired at a 45 degree angle with an inital velocity of 15 m/s. Find it's max height and kinetic energy when it is at it's max height.


    2. Relevant equations
    Ek=1/2mv^2
    Ep=mgh


    3. The attempt at a solution
    I tried breaking it down to x and y components, but I don't know if thats right.
     
  2. jcsd
  3. Feb 24, 2008 #2
    What is the kinetic and potential energy of the arrow as it is first fired? What is the velocity of the arrow at the maximum height?
     
  4. Feb 24, 2008 #3
    Max height has to do with potential energy. Kinetic energy at max height is a conceptual question and idea.
     
  5. Feb 24, 2008 #4
    that's all the info they gave me.
     
  6. Feb 24, 2008 #5
    No, what I mean is that you can figure out those two things I asked you from the information you are given. Think about what forces act on the arrow. Does the horizontal velocity ever change?
     
  7. Feb 24, 2008 #6
    Break the velocity into components.
     
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