Conservation of Energy max height

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SUMMARY

The discussion centers on calculating the maximum height and kinetic energy of an arrow with a mass of 0.2 kg, fired at a 45-degree angle with an initial velocity of 15 m/s. The relevant equations include kinetic energy (Ek = 1/2 mv²) and potential energy (Ep = mgh). The maximum height can be determined by analyzing the vertical component of the initial velocity and applying the conservation of energy principle, where kinetic energy at launch converts to potential energy at the peak height. The horizontal velocity remains constant throughout the flight, while the vertical velocity becomes zero at maximum height.

PREREQUISITES
  • Understanding of projectile motion and its components
  • Familiarity with the conservation of energy principle
  • Knowledge of basic physics equations for kinetic and potential energy
  • Ability to perform vector decomposition of velocity
NEXT STEPS
  • Calculate the vertical component of the initial velocity using trigonometric functions
  • Determine the maximum height using the formula Ep = mgh
  • Analyze the kinetic energy at launch and at maximum height
  • Explore the effects of air resistance on projectile motion
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy conservation, as well as educators seeking to clarify concepts related to projectile motion and energy transformations.

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Homework Statement


An arrow(mass=0.2kg) is fired at a 45 degree angle with an inital velocity of 15 m/s. Find it's max height and kinetic energy when it is at it's max height.


Homework Equations


Ek=1/2mv^2
Ep=mgh


The Attempt at a Solution


I tried breaking it down to x and y components, but I don't know if that's right.
 
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What is the kinetic and potential energy of the arrow as it is first fired? What is the velocity of the arrow at the maximum height?
 
Max height has to do with potential energy. Kinetic energy at max height is a conceptual question and idea.
 
Tedjn said:
What is the kinetic and potential energy of the arrow as it is first fired? What is the velocity of the arrow at the maximum height?

that's all the info they gave me.
 
No, what I mean is that you can figure out those two things I asked you from the information you are given. Think about what forces act on the arrow. Does the horizontal velocity ever change?
 
Break the velocity into components.
 

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