Conservation of Energy max height

AI Thread Summary
To find the maximum height and kinetic energy of an arrow fired at a 45-degree angle with an initial velocity of 15 m/s, one must analyze the motion using the equations for kinetic energy (Ek = 1/2mv^2) and potential energy (Ep = mgh). The arrow's initial kinetic energy can be calculated using its mass and initial velocity. At maximum height, the vertical component of the velocity becomes zero, while the horizontal component remains unchanged, allowing for the calculation of potential energy at that height. Understanding the conservation of energy principles is crucial, as the initial kinetic energy converts to potential energy at the peak of the trajectory. The discussion emphasizes the importance of breaking down the velocity into its components to solve the problem accurately.
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Homework Statement


An arrow(mass=0.2kg) is fired at a 45 degree angle with an inital velocity of 15 m/s. Find it's max height and kinetic energy when it is at it's max height.


Homework Equations


Ek=1/2mv^2
Ep=mgh


The Attempt at a Solution


I tried breaking it down to x and y components, but I don't know if that's right.
 
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What is the kinetic and potential energy of the arrow as it is first fired? What is the velocity of the arrow at the maximum height?
 
Max height has to do with potential energy. Kinetic energy at max height is a conceptual question and idea.
 
Tedjn said:
What is the kinetic and potential energy of the arrow as it is first fired? What is the velocity of the arrow at the maximum height?

that's all the info they gave me.
 
No, what I mean is that you can figure out those two things I asked you from the information you are given. Think about what forces act on the arrow. Does the horizontal velocity ever change?
 
Break the velocity into components.
 

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