A child whose weight is 267 N slides down a 6.10 m playground slide that makes an angle of 20.0° with the horizontal. The coefficient of kinetic friction between slide and child is 0.10. (a) How much energy is transferred to thermal energy? (b) If she starts at the top with a speed of 0.534 m/s, what is her speed at the bottom? my attempt: a)267sin30° - 0.1 x 267 cos 20° = 108.410 J b) ƩW = 1/2m(v final)^(2) - 1/2m(v initial)^(2) 108.410 J = 1/2m(v final)^(2) - 2.845J 111.255 = 1/2m(v final)^(2) .....v final = 2.858 m/s The answers are a) 153 J b) 5.45 m/s im not sure what I am doing wrong. can someone please help? thanks! EDIT: I figure out what i did wrong for part a. the answer is just mu n 0.1x267cos(20)x6.1 = 153.047 I still dont understand part b!? help please!